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- Timestamp:
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Jun 13, 2014, 1:59:09 PM (11 years ago)
- Author:
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Pedro Gea
- Comment:
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--
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- Added
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v3
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v4
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91 | 91 | Podemos reagrupar los términos en función de los parámetros {{{b_k}}} del siguiente modo: |
92 | 92 | {{{ |
93 | | | / (x_k-x_{k+1}) ,, x<x_k |
94 | | | b_k * | (x-x_{k+1}) ,, x<:[x_k, x_{k+1}] ,, k<q |
95 | | | \ 0 ,, x>x_{k+1} |
96 | | | / x_q ,, x<x_q |
97 | | E(x) = <| b_q * | x ,, x<:[x_q, x_{q+1}] |
98 | | | \ x_{q+1} ,, x>x_{q+1} |
99 | | | / 0 ,, x<x_m |
100 | | | b_m * | (x-x_m) ,, x<:[x_m, x_{m+1}] ,, m>q |
101 | | | \ (x_{m+1}-x_m) ,, x>x_{m+1} |
| 93 | | / x_k -x_{k+1} ,, x<x_k |
| 94 | | b_k * | x - x_{k+1} ,, x<:[x_k, x_{k+1}] ,, k<q |
| 95 | | \ 0 ,, x>x_{k+1} |
| 96 | | / x_k ,, x<x_k |
| 97 | E(x) = <| b_k * | x ,, x<:[x_k, x_{k+1}] ,, k==q |
| 98 | | \ x_{k+1} ,, x>x_{k+1} |
| 99 | | / 0 ,, x<x_k |
| 100 | | b_k * | x - x_k ,, x<:[x_k, x_{k+1}] ,, k>q |
| 101 | | \ x_{k+1} - x_k ,, x>x_{k+1} |
102 | 102 | }}} |
103 | 103 | A estos nuevos inputs los denominamos ''inputs-piecewise''. |
| 104 | |
| 105 | Podemos observar que el particionamiento del input, puede escribirse en los tres diferentes casos siguientes como: |
| 106 | {{{ |
| 107 | si x <: [x_a, x_{a+1}] ,, a>q ,, 0 <: [x_q, x_{q+1}] |
| 108 | |
| 109 | | 0 ,, k < q |
| 110 | P_k(x) = | x_{k+1} ,, k == q |
| 111 | | x_{k+1} - x_k ,, q < k < a |
| 112 | | x - x_k ,, k == a |
| 113 | | 0 ,, k > a |
| 114 | }}} |
| 115 | {{{ |
| 116 | si x <: [x_a, x_{a+1}] ,, a==q ,, 0 <: [x_q, x_{q+1}] |
| 117 | |
| 118 | | 0 ,, k < q |
| 119 | P_k(x) = | x_{k+1} ,, k == q |
| 120 | | x_{k+1} - x_k ,, q < k < a |
| 121 | | x - x_k ,, k == a |
| 122 | | 0 ,, k > a |
| 123 | }}} |
| 124 | {{{ |
| 125 | si x <: [x_a, x_{a+1}] ,, a>q ,, 0 <: [x_q, x_{q+1}] |
| 126 | |
| 127 | | 0 ,, k < q |
| 128 | P_k(x) = | x ,, k == q |
| 129 | | 0 ,, k > q |
| 130 | }}} |
| 131 | y comprobar que: |
| 132 | {{{Sum_k(P_k(x)) == x}}} |
| 133 | y de ahí el término particionamiento. |